-8n^2+50n+42=0

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Solution for -8n^2+50n+42=0 equation:



-8n^2+50n+42=0
a = -8; b = 50; c = +42;
Δ = b2-4ac
Δ = 502-4·(-8)·42
Δ = 3844
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3844}=62$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(50)-62}{2*-8}=\frac{-112}{-16} =+7 $
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(50)+62}{2*-8}=\frac{12}{-16} =-3/4 $

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